(-10x^2)-36x+16=0

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Solution for (-10x^2)-36x+16=0 equation:



(-10x^2)-36x+16=0
We get rid of parentheses
-10x^2-36x+16=0
a = -10; b = -36; c = +16;
Δ = b2-4ac
Δ = -362-4·(-10)·16
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-44}{2*-10}=\frac{-8}{-20} =2/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+44}{2*-10}=\frac{80}{-20} =-4 $

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